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Category 9 Example 1 - calculation not required

It can be observed that the values of a and b in the top equation are half of the bottom equation, but this is not true for the values of c. This implies that the ratios of a and b are same but different than that of c. Hence, the system has no solution.


Category 9 Example 2 - mental math for those good with dividing fractions

It can be observed that the values of a, b, and c in the top equation are six times of the bottom equation: 3 is six times of 1/2, 2 is six times of 1/3, and 6 is six times of 1. This implies that the ratios of a, b, and c are same. Hence, the system has infinitely many solutions.


 

Category 10 Example 1 - mental math

It can be observed that in the top equation the value of b is 4 times of the bottom equation. For the system to have no solution, the value of a in the top equation must also be 4 times of the bottom equation. (This will result in the same ratios of a and b.)

Since a = 1 in the bottom equation, it must be 4 in the top equation. Hence, 2n = 4 - -> n = 2.


Category 10 Example 2 - mental math

It can be observed that in the top equation the values of a and b are one-third of the bottom equation. For the system to have no solution, the value of c in the top equation cannot be one-third of the bottom equation. Hence k = c cannot be 1.


 

Category 11 Example 1 - mental math

It can be observed that in the top equation the value of b is 3 times of the bottom equation. Since the system has infinitely many solutions, the vales of a and c in the top equation must also be 3 times of the bottom equation (this will result in the same ratios of a, b, and c).

Hence, a = 12 and c = 3.

Category 11 Example 2 - mental math for those good with dividing fractions

It can be observed that in the top equation the value of c is 12 times of the bottom equation. Since the system has infinitely many solutions, the values of a and b in the top equation must also be 12 times of the bottom equation (this will result in the same ratios of a, b, and c).

Hence, a = 4 and b = 3.


 

Category 12 Example 1 - mental math

It can be observed that the value of b in the bottom equation is five times of the top equation. For the system to have one solution, the value of a = k in the bottom equation cannot be 5 times the value of a in the top equation. Hence, k cannot be 10.


Category 12 Example 3 - shortcut and may be mental math

The question asks for the value of 50x + 10y. It can be observed that if the two equations are added, the result is the value of 5x + y. The value can be multiplied by 10 to obtain the answer.


 

Category 14 Example 1 - mental math

Since the equation has infinitely many solutions, the coefficient of x in the left expression must be 9 and the constant in the right expression must be 6. Hence, k = 3 and c = 2.


Category 14 Example 4 - mental math

It can be observed that the constant in left and right expression is same. For the equation to have no solution, 0.5a cannot be 10. Hence, a cannot be 20.


 

Category 2 Example 1 - no calculation required

The slope and the y-coordinate of the y-intercept are given (a point with x = 0 is the y-intercept). Match them to the answer choices given as y = mx + b equation.


Category 2 Example 3 - no calculation required

The slope can be determined from the graph as rise/run. The y-intercept can be directly read from the graph. Match them to the answer choices given as y = mx + b equation.


 

Category 3 Example 1 - mental math

It can be read from the equation as C/B.


Category 3 Example 2 - mental math

The slope can be determined from the graph as rise/run. Match this with -A/B in each answer choice and eliminate the answer choices where the slope does not match.

The y-intercept can be read from the graph. Match it with C/B in the remaining answer choices.


 

Category 8 Example 1 - no calculation required

Use the transformation rule given in Key Points for left shift and match it with the answer choices.

Category 8 Example 2 - no calculation required

Match the reflected graph based on the transformation rule given in Key Points.

A candy store has reduced the original price of all the chocolate boxes by 10%. Ela bought one box of chocolates at the discounted price and paid $11.34 after addition of 5% sales tax. What was the original price, in dollars, of the box of chocolates Ela bought, excluding the sales tax?

Maps to Category 46 of my book.

 

Answer posted on 11/06/2021: Correct answer is 12.


Convert all the percentages to decimal.

10% reduction = 0.9.

5% sales tax = 1.05.


To determine the original price, divide the end price (price paid) by the above decimals.

11.34/(0.9x1.05) = 12

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